Question

For hydrogen atom the number of visible spectral line from n=6 to ground state will be

Answer 1

Answer:

15

Explanation:

The formula of no of visible spectral lines for single electronic system = (n2 - n1) (n2 -n1 +1) /2

So given n2=6 and n1=1 so by using this formula the answer is 15.

Answer 2

Answer:

n=6

as we know that,

$E n= \frac{ - Rch}{ {n}^{2} } \\ e1 = - 13.6eV \\ \\ \\ similarly \\ \\ e6 = \frac{ - 13.6}{36} \\ = - 0.37eV \\ \\ therefore \\ Eex = e6 - e1 \\ = 0.37 - 13.6 \\ = - 13.23eV$

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