Question

for if any A.P. d=10 then t28-t23=?​

Answer 1

Answer:

40

Step-by-step explanation:

In an A.P,d=10 then,

t

6

−t

2

=(a+5d)−(a+d)

=a+5d−a−d

=4d=4×10

=40 (Ans)

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