Question

for increasing the angular velocity of object by 10% the kinetic energy is to be increase by? please give me the answer immediately

Answer 1

this must be the answer. If not reply

Answer 2

The kinetic energy got increased by 21%.

The rotational kinetic energy of an object is given as:

K.E. = (1/2) × I × w²

where w is the angular velocity

I  is the moment of inertia around the axis of rotation

Given that angular velocity of object increases by 10%

So, new angular velocity w' = (100+10)% of w = 1.1w

So, the rotational kinetic energy of the object is:

K.E.' = (1/2) × I × w'²

= (1/2) × I × (1.1w)²                                         [As w' = 1.1w]

=  (1/2) × I × 1.21w²

= 1.21 K.E.                                                      [As K.E. =  (1/2) × I × w²]

So percentage by which kinetic energy got increased = ( K.E.' - K.E.)  × 100%

= (1.21-1) × 100%

= 21%