Question

for (int i= 1; i <= 5; i++), int sum = 0;
sum= sum+ (i+2);
Predict the value of sum after the execution​

Answer 1

Answer:

okay.

int i = 1.

I<=5.

true.

I++ I value increment +1.

i = 6.

now sum = sum +(i +2).

sum = 0+(6+2).

sum = 8.

Answer 2

Answer:

The value of the sum after the execution will be 25.

Explanation:

The given code block is:

int sum = 0;

for (int i= 1; i <= 5; i++)

sum= sum+ (i+2);

Look at the for loop, it will run five times(from 1 to 5)

Every time when for loop will run, it will add the value of sum and i+2.

• In the first iteration,
• i=1 sum =0
• sum = 0+(1+2) =3
• In the second iteration
• i=2 sum =3
• sum = 3+(2+2) = 7
• In the third iteration
• i=3 sum =7
• sum = 7+(3+2) = 12
• In the fourth iteration
• i=4  sum =12
• sum = 12+(4+2) = 18
• In the last fifth iteration
• i=5 sum = 18
• sum = 18+(5+2) = 25

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