Physics, asked by khandakarhabib209, 5 months ago

For light of wavelength = 6x10^(-7) m, it is found that in a thin film of air, 9 fringes
occur between two points. Deduce the difference
of film thickness between these points.

Answers

Answered by sayyedfarhan6655

0

Answer:

6E-7

Explanation:

6x10(-7)

=6E-7

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