For moving train velocity-time graph is shown in figure.
(i) What is the maximum speed of the train and how long it is maintained?
(ii) What are the acceleration in OA AB and BC part ?
(iii) Find total distance travelled by the train.
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Answered by
10
Answer:
(ii)OA=10/40 AB=10/(420-40) BC=(0-10)/(500-420)
(I)10m/s maintained in(420-40)s
(iii) 500×10
Answered by
1
Answer:
40
420
Co what is the maimum speed of the train and how long
it is maintaing!?
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