Question

For n=195, by Fermat's theorem an-2
a) d (modn)
b) 1(modn)
c) 0(modn)
d) a(modn)​

Answer 1

according to question option number "d" is correct. a(modn).

Answer 2

Answer: b) 1(modn)

Step-by-step explanation:

• According to fermat's theorem,

         $a^{p-1}=1(mod\ p)$

• Which means that if a number is in this form then its value will be calculated as above.
• So, $a^{n-2} =2(mod\ n)$.
• Here, n=195.

               $a^{196-2}a^{195-1}\\= 1(mod\ n) as\ n \ is\ 195$

• Hence, option b is the correct answer.

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