Question

For n=2 the correct value set of azimuthal and magnetic quantum number?

Answer 1

Answer:

For n =2,  l can be 0 and 1

for   l=0,    m=o

and for l=1,  m =-1, 0+1

Answer 2

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For n = 2,write the correct set of azimuthal and magnetic quantum numbers

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Given that the principal quantum number is 2

To find

• Azimuthal Quantum Number

• Magnetic Quantum Number

Azimuth Quantum Number is given by :

$\large{ \boxed{ \boxed{ \sf{l = n - 1}}}}$

Now,

$\hookrightarrow \: \sf{l = 2 - 1} \\ \\ \large{ \hookrightarrow \: \underline{ \boxed{ \sf{l = 1}}}}$

According to spdf notation,the electron is present in 2p orbital

Magnetic Quantum Number is given by :

$\large{ \boxed{ \boxed{ \sf{m = 2l + 1}}}}$

Putting value of "l",we get :

$\hookrightarrow \: \sf{m = 2(1) + 1} \\ \\ \hookrightarrow \: \sf{m = 2 + 1} \\ \\ \large{ \hookrightarrow \: \underline{ \boxed{ \sf{m = 3}}}}$

The electron would have the values 0,1 and -1 as it's magnetic number

This means that,the electron has have any one value for "m" from the above notations