For one mole close pqcked spheres,how many octahedral and tetrahedral voids are present
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Answer:
Octahedral voids = 6.022×10^23
Tetrahedral voids = 12.044×10^23
Explanation:
Each unit cells in closed packed structure contains 4 atoms.
No of unit cells in closed packed structure by one mole atoms is -
N = NA / 4
N = 6.022×10^23 / 4
N = 1.505×10^23 unit cells
Each unit cell contains 4 octahedral and 8 tetrahedral voids.
Number of octahedral voids is -
Octahedral voids = 4 × N
Octahedral voids = 4 × 1.505×10^23
Octahedral voids = 6.022×10^23
Number of tetrahedral voids is -
Tetrahedral voids = 8 × N
Tetrahedral voids = 8 × 1.505×10^23
Tetrahedral voids = 12.044×10^23
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