For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are: *
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Step-by-step explanation:
Given For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are
- Now construct the table, so we have
- Class – interval Frequency(f) Mid point (x) (f)(x)
- 0 – 5 15 2.5 37.5
- 5 – 10 16 7.5 120
- 10 – 15 x 12.5 12.5 x
- 15 – 20 8 17.5 140
- 20 – 25 y 22.5 22.5 y
- 25 – 30 8 27.5 220
- 30 – 35 6 32.5 195
- 35 – 40 4 37.5 150
- Total 70 862.5 + 12.5 x + 22.5 y
- Now we have Mean = 862.5 + 12.5 x + 22.5 y / 70
- Given Mean = 15.5
- So we get 862.5 + 12.5 x + 22.5 y / 70 = 15.5
- 862.5 + 12.5 x + 22.5 y = 1085
- 12.5 x + 22.5 y = 222.5
- 125 x + 225 y = 2225
- 5x + 9y = 89
- So we have x + y + 57 = 70
- Or x + y = 13
- We have two equations . Solving we get
- 5x + 9y = 89
- x + y = 13 multiply by 5
- 5x + 9y = 89
- 5x + 5y = 65
- So 4y = 24
- Or y = 6
- Substituting the value of y in the equation we get
- Now x + y = 13
- Or x + 6 = 13
- Or x = 13 – 6
- Or x = 7
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Answered by
2
Answer:
option d correct answer
Step-by-step explanation:
d) x=7 and y=6
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