Question

For P=400, R=12.5p.c.pod and N= 3 years
find compound interest​

Answer 1

$c.i = p{ ( \frac{r}{100} + 1)}^{t} \\ = > c.i = 400{( \frac{12.5}{100} + 1)}^{3} \\ = > c.i = 400 {( \frac{112.5}{100} )}^{3} \\ = > c.i = 400 \times \frac{112.5}{100} \times \frac{112.5}{100} \times \frac{112.5}{100} \\ = > c.i = 400 \times \frac{1125}{1000} \times \frac{1125}{1000} \times \frac{1125}{1000} \\ = > c.i = 569.53125$