Math, asked by Ramu111, 1 year ago

For p, q belongs to R; the roots of (p^2+q^2) x^2 +2x (p+q) +2 =0 are

Answers

Answered by abhi178
4
( P² + q²)x² +2x(P +q) +2 =0

use quadratic formula,
x = { -b ±√D }/2a

D = 4(P+q)² -8(p²+q²)
=4{ -p²-q² +2pq }
=4 { -(p-q)² }

=-4(p-q)²

x ={ -2(P+q)±2√-(p-q)²}/2(p² + q²)

={ -2(P+q) ±2i(p-q)}/2(p²+q²)

abhi178: dear this question related to complex no
Ramu111: how
abhi178: D = 2(p+q)² -2×4(p²+q²) = -4(p-q)² < 0
abhi178: so, no real roots present here
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