Question

for p(t)=t²-t+2,p(⅓)=​

Answer 1

Answer:

$\frac{16}{9}$

Step-by-step explanation:

$p(t) = {t}^{2} - t + 2 \\ p( \frac{1}{3} ) = ( { \frac{1}{3} })^{2} - \frac{1}{3} + 2 \\ = \frac{1}{9} - \frac{1}{3} + 2 \\ = \frac{1 - 3 + 18}{9} \\ \frac{ - 2 + 18}{9} = \frac{16}{9}$