Math, asked by fshabna26, 27 days ago

For p(x) = 2x2-3x+1, find p(0), p(1), p(-1).

Answers

Answered by atharvarangdale
0

Answer:

p(0) is 4

p(1) is 2

p(-1) is 0

Step-by-step explanation:

Considering 2*2 not 2x2

Answered by nariseamalavathi
3

p(x) = 2x {}^{2}   - 3x + 1 \\  \\ p(0) = 2(0) {}^{2}  - 3(0) + 1 \\ =  0 - 0 + 1 = 1 \\  \\ p(1) = 2(1) {}^{2}  - 3(1) + 1 \\  = 2 - 3 + 1 \\  = 3 - 3 \\  = 0 \\  \\ p( - 1) = 2( - 1) {}^{2}  - 3( - 1) + 1 \\  = 2(1) + 3 + 1 \\  = 2 + 4 \\  = 6

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