For p(x)=x^2+(k-7)x+(k+1) if sum n product of zeroes of polynomial are equal then k=......
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Answer:
Step-by-step explanation:
Sum of zeroes=-b/a
=-(k-7)
=-k+7..........(1)
Product of zeroes=c/a
=(k+1)..........................(2)
From equation 1 & 2
-k+7=k+1
2k=6
K=3
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