Math, asked by rajputjonty1954, 2 months ago

for p(x)=x³+1 find p(-1)​

Answers

Answered by aloknpandey125
1

Answer:

p (0)=(0-1)(0+1)

= -1×1

=-1

p (-1)=(-1-1)(-1+1)

= -2×0

=0

p (1)= (1-1)(1+1)

=0×2

=0

Step-by-step explanation:

Answered by kaunain28
0

Answer:

-2

Step-by-step explanation:

p(x)=x^3-1

p(1)=(1)^3-1

p(1)=1-1=0

p(-1)=(-1)^3=-1

p(-1)=-1-1=-2

therefore p(1)=0,p(-1)=-2

p(1)+p(-1)=0+(-2)=-2

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