Question

for p(y) = y²-9 find p(0), p(1), p(2)​

Answer 1

Answer:

p(0), p(1) and p(2) are -9, -8 and -5 respectively.

Step-by-step explanation:

p( y ) = y² - 9

Finding p(0) by substituting 0 in place of y

⟹ p(0) = (0)² - 9

⟹ p(0) =0 - 9

⟹ p(0) = - 9

Finding p(1) by substituting 1 in place of y

⟹ p(1) = (1)² - 9

⟹ p(1) = 1 - 9

⟹ p(1) = -8

Finding p(2) by substituting 2 in place of y

⟹ p(2) = (2)² - 9

⟹ p(2) = 4 - 9

⟹ p(2) = -5

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Here, p(y) is a function of y. In p(y) = y² - 9, y²-9 is the output and y is the input value. So, value of y²-9 chances as we change the value of y