Question

For parabola y^2=4y-4x ,the vertex is

Answer 1

y^2=4y - 4x 

=>y²=4(x-y)

=>y²+4y+4=4x-4

=>(y+2)²=4(x-1) which is the form of Y²=4aX

where X=x-1 and Y=y-2 and 4a=4,therefore a=1

For the vertex,

X=0,Y=0 i.e.,x+1=0,or x=1 and y-2=0,or y=2

Therefore coordinates of vertex are (1,2)