For preparing a buffer solution of ph 6 by mixing sodium acetate and acetic acid
Answers
Hey mate here is the answer to your question.
The pH of buffer solution which contains 6, by mixing sodium acetate and acetic acid ,
According to formula;
pH= Pka+log salt/acid
6 = 5+ 10/ 1
the ratio of the concentration of salt and acid should be (Ka = 10-5 )
answer will be according to rule
Hope this will be helpful
The pka value of acetic acid is 1.8*10^(-5)
ACOH = acetic acid
NaOAC = Sodium acetate
according to Henderson's Equation,
pH = pKa+log(salt/acid)
=> 6 = pKa+log(NaOAc/ACOH)
=> 6 = -log[1.8*10^(-5)]+log(NaOAc/ACOH)
=> 6 = 4.745 +log(NaOAc/ACOH)
=> log(NaOAc/ACOH) =1.255
=> [NaOAc]/[ACOH] =10^1.255 =17.98
The required ratio of concentration of sodum acetate and acetic acid is 17.98 to prepare a buffer solution of pH=6.
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its salt , or vice versa. Its pH remains unchanged when a small amount of strong acid or base is added to it. Example, the bicarbonate buffering system is used to maintain the pH of blood.