Question

For principal quantum number n =4 the total number of orbitals having l =3 is

Answer 1

7. They are m= -3, -2, -1, 0 ,1 ,2, 3

Answer 2

Answer: 7

Explanation:

Principle Quantum Number: This quantum number describes the size of the orbital. It is represented by n.

Azimuthal Quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1).

Magnetic Quantum Number: This quantum number describes the orientation of the orbitals. It is represented as $m_l$. The value of this quantum number ranges from $(-l\text{ to }+l)$. When l = 3, the value of $m_l$ will be -3, -2, -1, 0, +1, +2, =3.

For n=4, the value of l=3 will have 7 values of $m_l$ and hence 7 orbitals.