For principle quantum number, n = 4, the total number of orbitals having l = 3 is
(a) 3
(b) 7
(c) 5
(d) 9
Answers
Answered by
1
Answer:
7 is the answer
number of orbitals is 2l+1
=2(3)+1=6+1=7 orbitals
Answered by
2
Answer:
The answer is (c) = 7
Explanation:
Each subshell of quantum number l contains 2l+1 orbitals. Thus, for l=3, there are (2×3)+1=7 orbitals.
Hope this helps !
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