Question

for projectile motion Vi=2m/s and angle 30,Vy​

Answer 1

Answer:

Explanation:

Pawan own l o.

Answer 2

For projectile motion, initial velocity of body is 2m/s and projected at an angle of 30° with the horizontal.

To find : the vertical component of initial velocity is...

solution : body is projected with the speed of 2m/s at an angle of 30° with the horizontal.

so, velocity of body in vector form would be, u = 2(sin30° i + cos30° j)

= 2(1/2 i + √3/2 j)

= 1 i + √3 j

∴ horizontal component of velocity = 1 m/s

vertical component of velocity = √3 m/s

Therefore the vertical component of velocity is √3 m/s.

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