Question

For quadratic equation 10x2 + 10x + 1 = 0, what is the value of the
discriminant ?​

Answer 1

Answer:

D=√10²-4(1) = √100-40= √60

hence roots are real

Answer 2

The discriminant of 10x² + 10x + 1 = 0 is 60

Given :

The equation 10x² + 10x + 1 = 0

To find :

The discriminant of the equation

Concept :

General form of a quadratic equation is

ax² + bx + c = 0

The Discriminant of the quadratic equation is denoted by D and defined as

D = b² - 4ac

Solution :

Step 1 of 2 :

Write down the given Quadratic equation

Here the given Quadratic equation is

10x² + 10x + 1 = 0

Step 2 of 2 :

Find the discriminant

The given equation is 10x² + 10x + 1 = 0

Comparing with the general equation ax² + bx + c = 0 we get

a = 10 , b = 10 , c = 1

Hence discriminant of the quadratic equation

= b² - 4ac

$\sf = {( 10)}^{2} - 4 \times 10 \times 1$

$\sf = 100 - 40$

$\sf = 60$

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