Question

For quadratic equation 3x2 +√8x-16, the value of constant c is _________.

Answer 1

Answer:

c= -16

hope you got your answer

Answer 2

Step-by-step explanation:

Given that:

for the quadratic equation 3 X square + root 8 x minus 16 the value of constant C is

Expression:

$3 {x}^{2} + \sqrt{8} x - 16$

Solution: To find the value of c,

one should first write standard quadratic equation

Standard Quadratic equation

$a {x}^{2} + bx + c \: ,where \: a \neq0$

Now compare the given equation to standard equation

here

$a = 3 \\ \\ b = \sqrt{8} \\ \\ c = - 16$

Thus,For quadratic equation 3x² +√8x-16, the value of constant c is -16.

Hope it helps you.