Math, asked by sheghantebhagyashree, 3 months ago

For quadratic equation
10x  ^{2}  + 10x + 1 = 0
What is the value of the discriminant? ​

Answers

Answered by vaishubh1707
1

Answer:

60

Step-by-step explanation:

10x²+10x+1=0

a=10, b=10, c=1

discriminate= b²-4ac

= (10)²-4(10)(1)

= 100-40

=60

Answered by vijisekar
1

Step-by-step explanation:

discriminant ∆ = b² - 4ac

a \:  = 10 \: b = 10 \:  \: c \:  =1 \\  {b}^{2} - 4ac =  {10}^{2} - 4(10)(1) \\  = 100 - 40 \\  = 60

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