Question

for quantum no.of unpaired ele.of chlorine are (1)n=3 l=2m=0e=+1/2 (2)n=3l=1m=0e=+1/2 (3)n=3l=1m=+1e=0(4)n=3l=0m=-1e=+1/2​

Answer 1

Answer:

first we find electronic configurations of Cl

Cl = 1s2 2s2 2p6 3s2 3p5

here unpaired electron of Cl in 3p5

for p orbital , l= 1

m= -1,0 ,1

n = 3

For quantum no. of electron

n= 3

l= 1

m= 0

s= +1/2

so, right answer is option( 2)