For reaction BF, + NaH-P+Q
If Q is sodium salt, then incorrect statement is :
(T) Pis electron deficient compound
2)P forms adduct with PH3
3)Acidified MnO2.oxidizes Q into a coloured gas
(4) Q forms white precipitate with CaCl2, solution
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In Diborane structure, each Boron bonds with 4 hydrogen atoms. But Boron valency is 3. Each Boron gives 3 valence electrons but for the 4
th
bond, there is no electron from Boron side which makes it electron deficient.
(Refer to Image 2)
In AlCl
3
, Al atom bonds with 3 Cl atoms. But here it violates octet rule. There are no bonds or lone pairs, which makes the surrounding electron count 8. It has only 3 bonds which makes 6 electrons. So, it is an electron deficient compound. So, both AlCl
3
and B
2
H
6
are electron deficient compounds
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