Question

* For reaction, m1A+ m2 B =n1C+n2D
What will be value of Kc and what will be relation
of Kp and Kc ?​

Answer 1

Explanation:

Let the gaseous reaction is a state of equilibrium is-

aA

(g)

+bB

(g)

⇌cC

(g)

+dD

(g)

Let p

A

,p

B

,p

C

and p

D

be the partial pressure of A,B,C and D repectively.

Therefore,

K

c

=

[A]

a

[B]

b

[C]

c

[D]

d

.....(1)

K

p

=

p

A

a

p

B

b

p

C

c

p

D

d

.....(2)

For an ideal gas-

PV=nRT

⇒P=

V

n

RT=CRT

Whereas C is the concentration.

Therefore,

p

A

=[A]RT

p

B

=[B]RT

p

C

=[C]RT

p

D

=[D]RT

Substituting the values in equation (2), we have

K

p

=

[A]

a

(RT)

a

[B]

b

(RT)

b

[C]

c

(RT)

c

[D]

d

(RT)

d

⇒K

p

=

[A]

a

[B]

b

[C]

c

[D]

d

(RT)

[(c+d)−(a+b)]

⇒K

p

=K

c

(RT)

Δn

g

(From (1)]

Here,

Δn

g

= Total no. of moles of gaseous product − Total no. of moles of gaseous reactant

Hence the relation between K