Question

. For real number x, if the minimum value of
f(x)=x2+2bx+2c2 is greater than the
maximum value of g(x)=x2-2cx+b2. Then
(A.P.EAMCET-2018)​

Answer 1

Answer:

if the minimum value of f(x)

Answer 2

Answer:

y= x 2 −5x+9x

⇒yx 2 −(5y+1)x+9y=0

As x is real, discriminant ≥0

⇒(5y+1) 2 −36y 2 ≥0

⇒11y 2−10y−1≤0

∴y∈[− 111 ,1]

i.e. Maximum value of expression is 1.

Hence, option A.