For real numbers x and y, define x R y if and only if x – y + root2 is an irrational number. Then the relation R is
(A) reflexive (B) symmetric (C) transitive (D) none of these
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For every value of x belongs to R, x−x+
2
i.e.,
2
is an irrational number.
Therefore, it is reflexive.
Now Let's say x=
2
and y=2 then x−y+
2
=2
2
−2 which is irrational but when y=
2
and x=2,
x−y=
2
is not irrational;
∴ it is not symmetric.
Let x−y+
2
is irrational & y−z+
2
is irrational then in above case let x=1; y=
2
×2 & z=
2
Then x−z+
2
is not irrational, therefore the relation is not transitive.
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