Question

For real y, the number of solutions of the equation √y+3 + √y=1 is​

Answer 1

Answer:

Given: equation

3y+1

=

y−1

To find the roots of the equation

Sol:

3y+1

=

y−1

Take square on both sides, we get

3y+1=y−1

⟹3y−y=−1−1

⟹2y=−2

or, y=−1

Step-by-step explanation:

hope helps