Question

for same speed of projection range are equal for angle theta height is h1 and for other is h2 proove that Range =root 16 h1 h2

Answer 1

Answer:

For equal ranges,body should be projected with angle θ or (90

o

−θ) from the horizontal.

and for these angles:

h

1

=

2g

u

2

sin

2

θ

and h

2

=

2g

u

2

cos

2

θ

By multiplication of both height,

h

1

h

2

=

4g

u

2

sin

2

θcos

2

θ

=

16

1

(

g

u

2

sin2θ

)

2

⇒16h

1

h

2

=R

2

⇒R=4

h

1

h

2