Question

for second order reaction A+2B P where p stands for the product the differential rate is dx/dt = K₂ (a-x) (b-2x) integrate the équaton.
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Answer 1

Answer:

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Answer 2

Given:

Second order reaction A+2B.

To find:

$\frac{dx}{dt} = K_{2} (a-x) (b-2x)$

Explanation:

$\frac{dx}{dt}=k(a-x)^{2}$

$A$→$B$

$\frac{t1}{2}=\frac{1}{[A].K}$

$\frac{t1}{2}=\frac{1}{a.k}$

Therefore, the product of differential is $\frac{1}{a.k}$ .