Question

For sets A, B and C, let f : A → B such that f -1

exists. Is f bijective ?​

Answer 1

Answer:

I am having trouble proving this problem. If f:[a,b]→[c,d] is a continuous bijection and f(a)<f(b) then prove that for all a<x<b, then f(a)<f(x)<f(b). I was told that I should use a contradiction, then the Intermediate Value Theorem. I decided to rewrite f(a)<f(x)<f(b) as the statement f(a)<f(x) and f(x)<f(b). When I use proof by contradiction, I then have the statement if a<x<b then f(a)≥f(x) or f(x)≥f(b). I am not sure what I should do next in order to use the Intermediate Value Theorem.

Step-by-step explanation:

MARK BRAINLIEST