Question

For SO2Cl2→ SO2 + Cl2, Pressure of
SO2CI2 changed from 5 atm to 4 atm in 10
min. Then, pressure of so2cl2, at the end of
30 minutes will be (in atm)
1) 2.56 2) 3.56 3) 4.56 4) 5.56​

Answer 1

2.56 atm will be the pressure of SO2Cl2, at the end of  30 minutes.

Explanation:

Given that,

The reaction = SO2Cl2 → SO2 + Cl2

Pressure at the initial stage = 5 atm

After 10 minutes, the pressure = 4 atm

Now, by using the rate law, we will find the rate constant(K)

So,

Rate constant (K) = $\frac{2.303}{t}log \frac{[A_{0}] }{[A]}$

⇒ $K = \frac{2.303}{10} log \frac{5}{4}$

∵ K = 0.0223

A.T.Q.

Time (t) = 30 minutes

Concentration by the end of 30 minutes,

$\frac{2.303}{t}log \frac{[A_{0}] }{[A]}$

= $\frac{2.303}{30}log \frac{5 }{[A]}$

⇒ (0.0223 * 30)/2.303 = log 5 - log A

⇒  0.2907 = (log5 - logA)

⇒  logA = (0.6989−0.2907)

⇒ 0.40

⇒ [A] = $10^{0.40}$

∵ 2.56

Thus, option 1 i.e. 2.56 atm is the pressure of SO2Cl2 after 30 minutes.

Learn more: Calculate the pressure

brainly.in/question/40327594