Question

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24 Joule work is done in moving a charge q between two points having Potential difference of 12 volts. Find the value of Q. ​

Answer 1

Answer:

The value of Q is 2 Coulomb.

Explanation:

Given:

Work done = 24 Joule

Potential difference = 12 volts

To Find:

The value of charge ‘Q’.

Formula to be used:

$\sf Potential\ difference \ (v) \ = \ \dfrac{work \ done}{charge}$

Solution:

We know that,

$\sf Potential\ difference \ (v) \ = \ \dfrac{work \ done}{charge}$

$\implies \sf v = \dfrac{w}{Q}$

$\implies \sf Q = \dfrac{w}{v}$

$\implies \sf Q = \dfrac{24}{12}$

$\implies \sf Q = 2 \ Coulomb$

$\therefore$ The value of charge (Q) is 2 Coulomb.