For sulphur dioxide calculate mass of 2.8 moles and 280 molecules
Answers
Answered by
12
To calculate mass of 2.8 moles and 280 molecules
===============================>>>>>
hence
Molecular mass of 1 molecule = S + 2×O
=32 + 2× 16
=32 + 32
= 64g
so,as we know
one mole of any substance contains 6.022×10^23 molecules
show 2.8 mole of that substance will contain = 6.022×10^23 × 2.8
=17.4616 × 10^23 molecules
=1.74616 × 10^24 molecules
but here it is asked for 2.8 mole + 280 molecules )
so,
the total number of molecules = (1.74616×10^24+ 280)
= (174.616×10^22+ 280)
= 1.74616×10^24 molecules
so,mass of 1.74616×10^24 molecules
= 64× 1.74616× 10^24 g
= 1.1175424× 10^26 g
mass are present
===============================>>>>>
hence
Molecular mass of 1 molecule = S + 2×O
=32 + 2× 16
=32 + 32
= 64g
so,as we know
one mole of any substance contains 6.022×10^23 molecules
show 2.8 mole of that substance will contain = 6.022×10^23 × 2.8
=17.4616 × 10^23 molecules
=1.74616 × 10^24 molecules
but here it is asked for 2.8 mole + 280 molecules )
so,
the total number of molecules = (1.74616×10^24+ 280)
= (174.616×10^22+ 280)
= 1.74616×10^24 molecules
so,mass of 1.74616×10^24 molecules
= 64× 1.74616× 10^24 g
= 1.1175424× 10^26 g
mass are present
gautam96:
if it helps then please mark me brainlist
Similar questions