Question

for taking a bath, water at 40°C is required . calculate the mass of cold Water at 15°C which is to be added to 60 kg water at 100°C for bathing purpose​

Answer 1

Answer:

I hope this answer will help you

Answer 2

Energy added to cold water, E1

E1 = m•Cp•ΔT = 6 x 4.187x(42-20) = 6x4.187x22

Energy lost by hot water, E2:

E2 = X(CpΔT) = X x 4.187 x (75-42) =X x 4.187 x 33

So, since E1 = E2

6x4.187x22 = X x 4.187 x 33

X = 6x22/33 = 4.0kg

So the mass of the hot water added to the 6kg of cold water is 4.0kg