Question

For

$\rm\dashrightarrow{Best User}$
$\rm\dashrightarrow{Moderator}$

$\pink{\boxed{Spam\: Free \: Answer}}$

​

Answer 1

Answer:

• tex]\rm\dashrightarrow{Moderator}[/tex]

$\pink{\boxed{Spam\: Free \: Answer}}$

Step-by-step explanation:

1. tex]\rm\dashrightarrow{Moderator}[/tex]

$\pink{\boxed{Spam\: Free \: Answer}}$

Answer 2

Answer:

Let, AB be the height of the plane when it started landing =h.

and AC be the distance travelled by the plane during the landing.

Time taken =54 sec = 54/3600

From diagram,

l∥BC⇒∠ACB=20o

AC = Distance = Speed×time = 200×54/3600km = 3 km

From ΔABC

sin20o=ACAB

⇒0.342=3h

⇒h=3×0.342

⇒h=1.026

Hence, the height of the plane was 1.026 km.