For the AP :-3,-7,-11.., can we find a30-a20 without actually finding a30 and a20 ? Give reason
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Step-by-step explanation:
∵ nth term of an AP, an = a + (n-1)d
∴ a30 = a + (30 - 1)d = a + (30 - 1)d = a + 29d ...(i)
and a20 = a + (20 - 1)d = a + 19d
Now, a30 - a20 = (a + 29d) - (a+19d) = 10d
and from given AP common difference, d = -7-(-3) = -7+3
= -4
∴ a30 - a20 = 10(-4) = - 40
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