Question

For the arrangement shown in the Figure the tension
in the string is [Given : tan⁻¹(0.8) = 39° ] )
(a) 6 N (b) 6.4 N
(c) 0.4 N (d) zero.

Answer 1

Answer :  D

Solution :

If alpha represent angle of repose, then, tan α = 0.8

α = tan−1  (0.8) = 39∘

The given angle of inclination is less is less than the angle of repose. So, the 1 kg block has no tendency to move. [note that mg sin θ is exactly balanced by the force of friction. So,  T= 0 .]