Question

For the balanced equation 2Al(s) + 3CuCl2(aq) -> 2Cu(s) + 3AlCl3(aq)


How many grams of CuCl2 are needed to react with 48.5 g of Al?

Answer 1

Answer:

2:3::48.5:x

145.5 :2x

X=72.75g

Explanation:

2 moles of al : 3 moles of cucl2 :: grams of al : grams of cucl2(which we need to calculate).

As per the gay lussacs law.