Question

FOR THE BOX TO SATISFY CERTAIN REQUIREMENTS, ITS LENGTH MUST BE 3 UNITS GREATER THAN THE WIDTH, AND ITS HEIGHT MUST BE 2 UNITS LESS THAN THE WIDTH.
A) If width is taken as x, find the polynomials represents the volume of the box
B) If it must have a volume of 18 units, what must be its length and height?

Answer 1

Answer:

A) length=x+3units

height=x-2units

B)l*b*h=volume

OR,(x+3)+(x-2)+x=18

OR,x=17/3

Step-by-step explanation:

Hope it helps