Question

For the cell ag|ag^+||cu^2+|cu, which initially contains

Answer 1

CSol.

Quantity of electricity passed

= 9.65 x 60 x 60 C

= 34740 C

Ag+ ions deposited

= 34740 / 96500

=0. 36 mole

Cu2+ ions deposited

= 34740 / ( 2 x 95600 )

= 0.18 mole

[ Ag + ] left = 1 - 0.36

= 0.64 M

[ Cu + ] left = 1 - 0.18

= 0.82 M

Cell reaction

Cu+ + 2Ag+ ----> Cu 2+ + 2Ag