For the cell : (-) Pt | H (100kPa) | A(CA) || H+ (1mol.L-¹) | H (100kPa) | Pt(+), which is a solution to make Ecell to be highest?
A. 0.1 mol.L-¹ HCI
B. 0.1 mol.L-¹ HAc + 0.1 mol.L-¹ NaAc
c. 0.1 mol.L-¹ HAc
D. 0.1 mol.L-¹ H2SO4
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Answer:
Orion b is the answer
Explanation:
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Answer:
E
cell
=
1
0.0591
log
10
[H
+
]Anode
[H
+
]Cathode
E
cell
=0.06[pH Anode−pH Cathode]....(1)
pH Anode=pK
a
+log[
HA
]=4+log
1
0.1
=3
pH Cathode=4 (from eq. 1)
E
cell
=−0.06 V.
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