Question

For the cell reaction
Mg +2Ag (0.0001M) - Mg (0.01M) + 2Ag
E' = 3.177 V then what will be the value of E.
for the above reaction ?
(1) 2.5 (2) 3.0 (3) 3.2 (4) 3.8​

Answer 1

Answer:

2 3.0

Explanation:

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Answer 2

Answer:

3.0

Explanation:

3.177-0.0296 log (10)2/(log)8

3.177 -0.0296 log (10)6

3.177 - 6×0.0296

3.177-0.1776

2.9994

3.0