Question

For the circuit below (Figure 1),R1= 200Ω,R2= 400Ω,R3= 500Ω,Vs= 10V, andIs= 0.5A. Use MESH ANALYSIS to solve forI1in amps.

Answer 1

Answer:

Explanation:

I2 = 0.5A

I = I1 + 0.5

using kvl in first loop

10-(I1+0.5)400-500I1 = 0

I1 = -0.21

I = -0.21+ 0.5

 = 0.288