Question

For the circuit given below, calculate equivalent resistance between P and Q.​

Answer 1

Answer

option (C) $\dfrac{5R}{6}$

Solution

is in attachment.........

Answer 2

Explanation:

$\sf The\:first\:three\: resistors\:are\:in\:parallel \: \\ \\ \sf so \frac{1}{ {R}_{eq1}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} \\ \\ \sf{ R}_{eq1} = \frac{R}{3} \\ \\ \sf Other\:two\:resistors \:are\:in\:parallel \\ \\ \frac{1}{{R}_{eq}} = \frac{1}{R} + \frac{1}{R} \\ \\ \sf{ R}_{eq2} = \frac{R}{2} \\ \\ \sf {R}_{eq1} \:and\:{R}_{eq2} \:are\:in\:series \\ \\ \sf {R}_{eq} = {R}_{eq1} + {R}_{eq2} \\ \\ \sf {R}_{eq} = \frac{R}{3} + \frac{R}{2} \\ \\ \sf \boxed{\bold{\red {{R}_{eq} = \frac {5R}{6}}}}$

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