Question

For the circuit shown below the current I flowing through the circuit will be
Picture

Answer 1

Answer:

I = 2

Explanation:

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Answer 2

The current flowing in the circuit is 2 A.

Given,

Three resistors,

R1=3 ohm

R2=3 ohm

R3=3 ohm

Voltage supplied by the battery=2 V.

To find,

the current flowing through the circuit.

Solution:

The three resistors in the circuit are connected in parallel.

The equivalent resistance of resistors connected in parallel is calculated as:

$\frac{1}{Rnet}=\frac{1}{R1}+ \frac{1}{R2} +\frac{1}{R3}$

If n resistors of value R each are connected in a parallel combination, the equivalent resistance comes as:

$Rnet=\frac{R}{n}$

As the value of each resistor connected in the parallel combination is 3 ohm and there are three of them, the equivalent resistance of the resistors connected in the circuit will be:

$Rnet=\frac{3 ohm}{3}\\ Rnet= 1ohm.$

The potential difference(voltage) in a circuit is equal to product of the current supplied by the circuit and the resistance offered by the circuit.

$V=IR$

The current flowing in the circuit is:

$2=1XI\\I=\frac{2}{1} \\I=2A.$

Hence, the current is 2 ampere.

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