Question

for the circuit shown in below figure a )find the value of the supply voltage v and b ) the value of current I​

Answer 1

Answer:

10A

Explanation:

It can be clearly seen that

The resistances, $R_1, R_2, R_3$ are in parallel.

Also, we know that Voltage across resistances in parallel is always same.

The given values are:

$R_1$ = 10 Ω

$R_2$ = 20 Ω, $I_2 = 3 A$

$R_3$ = 60 Ω

$R_2$ and $I_2$ are given so voltage can be calculated across $R_2$:

Formula:

$V=I \times R$

$V = 3 \times 20 = 60V$

The resistances, $R_1, R_2, R_3$ are in parallel.

The formula for equivalent resistance:

$\dfrac{1}{R} = \dfrac{1}{R_1} +\dfrac{1}{R_2} +\dfrac{1}{R_3}\\\Rightarrow \dfrac{1}{R} = \dfrac{1}{10} +\dfrac{1}{20} +\dfrac{1}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{6+3+1}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{10}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{1}{6}\\\Rightarrow R = 6\ ohm$

Total Resistance, R = 6Ω

Total voltage, V= 60 V

Putting the values of V and R:

$V = I \times R\\\Rightarrow 60= I \times 6\\\Rightarrow I = 10 A$

Answer 2

Answer:

10A

Explanation:

It can be clearly seen that

The resistances, R_1, R_2, R_3R

1

,R

2

,R

3

are in parallel.

Also, we know that Voltage across resistances in parallel is always same.

The given values are:

R_1R

1

= 10 Ω

R_2R

2

= 20 Ω, I_2 = 3 AI

2

=3A

R_3R

3

= 60 Ω

R_2R

2

and I_2I

2

are given so voltage can be calculated across R_2R

2

:

Formula:

V=I \times RV=I×R

V = 3 \times 20 = 60VV=3×20=60V

The resistances, R_1, R_2, R_3R

1

,R

2

,R

3

are in parallel.

The formula for equivalent resistance:

\begin{gathered}\dfrac{1}{R} = \dfrac{1}{R_1} +\dfrac{1}{R_2} +\dfrac{1}{R_3}\\\Rightarrow \dfrac{1}{R} = \dfrac{1}{10} +\dfrac{1}{20} +\dfrac{1}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{6+3+1}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{10}{60}\\\Rightarrow \dfrac{1}{R} = \dfrac{1}{6}\\\Rightarrow R = 6\ ohm\end{gathered}

R

1

=

R

1

1

+

R

2

1

+

R

3

1

⇒

R

1

=

10

1

+

20

1

+

60

1

⇒

R

1

=

60

6+3+1

⇒

R

1

=

60

10

⇒

R

1

=

6

1

⇒R=6 ohm

Total Resistance, R = 6Ω

Total voltage, V= 60 V

Putting the values of V and R:

\begin{gathered}V = I \times R\\\Rightarrow 60= I \times 6\\\Rightarrow I = 10 A\end{gathered}

V=I×R

⇒60=I×6

⇒I=10A